题目
原题在此
解析
点踩比点赞多的一道题,配不上中等难度.你可以用任意方式遍历二叉树直到找到target为止.
代码
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   | class Solution { public:     TreeNode* getTargetCopy(TreeNode* original, TreeNode* cloned, TreeNode* target) {         if(original == target || original == NULL) return cloned;         TreeNode *t = getTargetCopy(original -> left, cloned -> left, target);         if(t == NULL) t = getTargetCopy(original -> right, cloned -> right, target);         return t;             } };
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